SOLUTION: 3[(2-3)^2 + (6 - 4)^2] I have not done this in quite a while and was needing some assistance. Can you please take a look at it and qive me some help. Thank you very much.

Algebra ->  Expressions-with-variables -> SOLUTION: 3[(2-3)^2 + (6 - 4)^2] I have not done this in quite a while and was needing some assistance. Can you please take a look at it and qive me some help. Thank you very much.      Log On


   

Question 347721: 3[(2-3)^2 + (6 - 4)^2]
I have not done this in quite a while and was needing some assistance. Can you please take a look at it and qive me some help. Thank you very much.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
3[(2-3)^2 + (6 - 4)^2] ... Start with the given expression.


3[(-1)^2 + (2)^2] ... Subtract.


3[1 + 4] ... Square each term.


3[5] ... Add


15 ... Multiply


So 3[(2-3)^2 + (6 - 4)^2] = 15


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim