SOLUTION: The hypotenuse of a right triangle is 22 m long. The length of one leg is 10 m less than the other. Find the lengths of the legs.

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Question 347708: The hypotenuse of a right triangle is 22 m long. The length of one leg is 10 m less than the other. Find the lengths of the legs.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x & x-10 be the 2 sides.
x^2+(x-10)^2=22^2
x^2+x^2-20x+100=484
2x^2-20x+100-484=0
2x^2-20x-384=0
2(x^2-10x-192)=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(10+-SQRT[-10^2-4*1*-192])/2*1
x=(10+-sqrt[100+768])/2
x=(10+-sqrt868)/2
x=(10+-29.46)/2
x=39.46/2
x=19.73 ans.
x=(10-29.46)/2
x=-19.46/2
x=-9.73 ans.