SOLUTION: Let h(t)=(5t-4)/(t-2). In each case, find all the real number solutions (if any) for the given equation. If there are no solutions, enter "NONE".
h(t)=15
h(t)=0
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-> SOLUTION: Let h(t)=(5t-4)/(t-2). In each case, find all the real number solutions (if any) for the given equation. If there are no solutions, enter "NONE".
h(t)=15
h(t)=0
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Question 347699: Let h(t)=(5t-4)/(t-2). In each case, find all the real number solutions (if any) for the given equation. If there are no solutions, enter "NONE".
h(t)=15
h(t)=0
You can put this solution on YOUR website! Your reply suggests: the real task at hand, is in fact: "In each case, find all the real number solutions (if any) for the given equation."
where "in each case" evidently refers to a number of given equations:
.
Would recommend visitng the idea that "0" in the denominator is not allowed: therefore the real number solutions for this particular equation would be:
.
All real numbers with the exception of t=2
Hi,
*Note: Substitute the value of t given for t.
h(t)=(5t-4)/(t-2)
.
h(15)=(75-4)/(15-2)
h(15)= 71/13
.
h(0) = -4/-2
h(0) = 2
