SOLUTION: 1.(a)given the matrix=A {2 3},what ar its dimension {0-1} {1 4} b)can these matrices be multiplied,why or why not? {2} {3 0} {4} {-2 3} {0} {1 2}

Algebra ->  Matrices-and-determiminant -> SOLUTION: 1.(a)given the matrix=A {2 3},what ar its dimension {0-1} {1 4} b)can these matrices be multiplied,why or why not? {2} {3 0} {4} {-2 3} {0} {1 2}      Log On


   



Question 347597: 1.(a)given the matrix=A
{2 3},what ar its dimension
{0-1}
{1 4}

b)can these matrices be multiplied,why or why not?
{2} {3 0}
{4} {-2 3}
{0} {1 2}

Found 2 solutions by Edwin McCravy, Fombitz:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
1. (a) Given the matrix A=%28matrix%283%2C2%2C2%2C3%2C0%2C-1%2C1%2C4%29%29,
what are its dimensions?
Dimensions are "down by across".  It is 3 elements down
and 2 elements across.  So it's a 3 by 2.

(b) Can these matrices be multiplied? Why or why not?
%28matrix%283%2C1%2C2%2C4%2C0%29%29%28matrix%283%2C2%2C3%2C0%2C-2%2C3%2C1%2C2%29%29

No they can't, because the matrix on the left is a 3 by 1 matrix and the
matrix on the right is a 3 by 2 matrix.

You can only multiply a "p by q" matrix on the left by a "q by r" matrix 
on the right and get a "p by r" matrix.
  
        (p by q)×(q by r) = (p by r)

The "inner" dimensions q must be the same, and if so, then the product  
matrix will have the "outer" dimensions, p by r.  Examples:

A 6 by 5 matrix on the left can be multiplied by a 5 by 9 matrix on the right
to give a 6 by 9 matrix, because the inner dimensions are both 5 and the outer
dimensions are 6 by 9.

        (6 by 5)×(5 by 9) = (6 by 9)

A 3 by 1 matrix on the left can be multiplied by a 1 by 3 matrix on the right
to give a 3 by 3 matrix, because the inner dimensions are both 1 and the outer
dimensions are 3 by 3. 

        (3 by 1)×(1 by 3) = (3 by 3)

A 1 by 3 matrix on the left can be multiplied by a 3 by 1 matrix on the right
to give a 1 by 1 matrix, because the inner dimensions are both 3 and the outer
dimensions are 1 by 1.

        (1 by 3)×(3 by 1) = (1 by 1)

A 58 by 29 matrix on the left can be multiplied by a 29 by 73 matrix on the
right to give a 58 by 73 matrix, because the inner dimensions are both 29 and
the outer dimensions are 58 by 73.

        (58 by 29)×(29 by 73) = (58 by 73)

However, in your problem (b), a 3 by 1 matrix on the left cannot be multiplied
by a 3 by 2 matrix on the right, because the inner dimensions are 1 and 3 are
they are not the same. 

        (3 by 1)×(3 by 2)
is not defined because the inner dimensions are not the same.


If you had been given these matrices instead:

%28matrix%281%2C3%2C2%2C4%2C0%29%29%28matrix%283%2C2%2C3%2C0%2C-2%2C3%2C1%2C2%29%29

then you would have had a 1 by 3 matrix on the left to multiply by a 3 by 2
matrix on the right, and they could be multiplied because the inner dimensions
are both 3.  The product matrix would be a 1 by 2 matrix because they would be
the outer dimensions.

        (1 by 3)×(3 by 2) = (1 by 2)

However if you wrote the second one on the left and the first one on the right
like this:

%28matrix%283%2C2%2C3%2C0%2C-2%2C3%2C1%2C2%29%29%28matrix%281%2C3%2C2%2C4%2C0%29%29
 
you could not multiply them because the inner dimensions would not be the same:

        (3 by 2)×(1 by 3 is not defined.  

The commutative principle does not hold for matrix multiplication like it
holds for ordinary number multiplication.

That is when you multiply 2×3 you get 6, which is the same as when you
multiply 3×2.  So the commutative principle holds for ordinary number
multiplication.  

Notice this however.  When you multiply 

%28matrix%282%2C2%2C1%2C4%2C3%2C2%29%29%28matrix%282%2C2%2C5%2C6%2C-3%2C0%29%29, 

and they can be multiplied, because

        (2 by 2)×(2 by 2) = (2 by 2)

the inner dimensions are the same,

you get this 2 by 2 matrix  %28matrix%282%2C2%2C-7%2C6%2C9%2C18%29%29

But when you multiply 

%28matrix%282%2C2%2C5%2C6%2C-3%2C0%29%29%28matrix%282%2C2%2C1%2C4%2C3%2C2%29%29,

and they can be multiplied, too, because

        (2 by 2)×(2 by 2) = (2 by 2)

the inner dimensions are the same,

you get this 2 by 2 matrix  %28matrix%282%2C2%2C23%2C32%2C-3%2C-12%29%29

So if you reverse the order of two matrices, even if they can still be 
multiplied, you don't get the same answer.

Edwin

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
a) 3 x 2 (rows x columns)
.
.
.
b) No, the first is 3 x 1 and the second is 3 x 2.
The numbers of columns of the first matrix must match the number of rows of the second to allow for matrix multiplication.