SOLUTION: A rectangle has a perimeter of 40 inches. If the longer side is (4x+8) inches and the shorter side is (3x-2) inches, then what are the deminsions of the rectangle?

Algebra ->  Rectangles -> SOLUTION: A rectangle has a perimeter of 40 inches. If the longer side is (4x+8) inches and the shorter side is (3x-2) inches, then what are the deminsions of the rectangle?      Log On


   

Question 347445: A rectangle has a perimeter of 40 inches. If the longer side is (4x+8) inches and the shorter side is (3x-2) inches, then what are the deminsions of the rectangle?
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
We use P = 2L + 2W

Let P = 40

Let (4x + 8) = length or longer side

Let (3x - 2) = width of shorter side

40 = 2(4x + 8) + 2(3x - 2)

Can you finish?