Question 347418: Find four consecutive even integers such that the sum of twice the first, five times the second, and four times the third divided by the three times the fourth equals 3.
Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the numbers be x,x+2,x+4,x+6
..
2x+5(x+2)+4(x+4)/3(x+6)=3
2x+5x+10+4x+16=9(x+6)
11x+26= 9x+54
11x-9x=54-26
2x=28
x= 14
.....
14,16,18,20
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