SOLUTION: Each side of a sqaure is 4 meters long. When each side is increased by x meters, the area is doubled. Find the value of x.

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Question 347264: Each side of a sqaure is 4 meters long. When each side is increased by x meters, the area is doubled. Find the value of x.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
2*4^2=(4+x)^2
2*16=16+8x+x^2
x^2+8x+16-32=0
x^2+8x-16=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(-8+-sqrt[8^2-4*1*-16])/2*1
x=(-8+-sqrt[64+64])/2
x=(-8+-sqrt128)/2
x=(-8+-11.314)/2
x=(-8+11.314)/
x=3.314/2
x=1.657 ans. for the increased length of the sides.
Proof:
2*4^2=(4+1.657)^2
2*16=5.657^2
32=32