SOLUTION: Here is the problem: "A line perpendicular to x+3y=5 passes through (1,1). What is the equation of the line in standard form?" Thanks!

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Question 347208: Here is the problem:
"A line perpendicular to x+3y=5 passes through (1,1). What is the equation of the line in standard form?"
Thanks!
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Step 1: Solve the given equation for in terms of everything else. Then your given equation will be in slope intercept form, i.e. .

Step 2: Determine the slope of the given line by inspection of the coefficient on in the result of step 1.

Step 3: The slope of perpendicular lines are negative reciprocals, that is:



So take the result of Step 2 and calculate the negative reciprocal.

Step 4: Use the point-slope form of an equation of a line:



where are the coordinates of the given point and is the slope calculated in Step 3.

Step 5: Arrange your equation into Standard Form, i.e. . Some texts require that , , and be integers.


John

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