SOLUTION: Find the perimeter of ΔABC with vertices A(-5,-2), B(-2,-2), and C(-5,2).

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Question 347036: Find the perimeter of ΔABC with vertices A(-5,-2), B(-2,-2), and C(-5,2).
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

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The vertical leg is AC=2-%28-2%29=4
The horizontal leg is AB=-2-%28-5%29=3
You can use the Pythagorean theorem to find BC.
BC%5E2=3%5E2%2B4%5E2
BC=sqrt%289%2B16%29
BC=sqrt%2825%29
BC=5
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P=AB%2BBC%2BAC
P=3%2B4%2B5
highlight%28P=12%29