SOLUTION: Find the vertex, the line of symmetry,and the maximum or minimum value of f(x). Graph the fuction. f(x)=1/2(x+2)^2+8 Please help.

Algebra ->  Graphs -> SOLUTION: Find the vertex, the line of symmetry,and the maximum or minimum value of f(x). Graph the fuction. f(x)=1/2(x+2)^2+8 Please help.      Log On


   

Question 346866: Find the vertex, the line of symmetry,and the maximum or minimum value of f(x). Graph the fuction. f(x)=1/2(x+2)^2+8 Please help.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
a general equation for a parabola (quadratic) is ___ y = a(x - h)^2 + k

the vertex is (h,k) [which is also the max or min]

the axis of symmetry passes through the vertex , the equation is ___ x = h


graph%28300%2C+300%2C+-8%2C+4%2C+-1%2C+12%2C+%281%2F2%29%28%28x%2B2%29%5E2%29%2B8%29