SOLUTION: Find two consecutive integers such that 2 times the lesser is 19 less than 3 times the greater.

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Question 346780: Find two consecutive integers such that 2 times the lesser is 19 less than 3 times the greater.
Found 2 solutions by nyc_function, ewatrrr:
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
I will give you the equation and you can finish.

x and x + 1 are the two consecutive integers we are searching for.

Let x = the smaller integer

Let x + 1 = the bigger integer

2x = 3(x + 1) - 19

Can you finish?



Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
*Note: consecutive integers differ by one and can be represented by:
n and (n+1)
.
The question states the following to be true:
Write as You read:
2%2An+=+3%2A%28n%2B1%29-19
.
Simplify and solve for n.
2%2An+=+3%2An%2B3-19
16=+n
.
The two Integers are 16 and 17
.
Check Your answer:
32 = 51 - 19