SOLUTION: What is the center of the circle x2 + y2 - 2x - 12 = 0?

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Question 346523: What is the center of the circle x2 + y2 - 2x - 12 = 0?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the caret to denote exponentiation, x^2=x%5E2.
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Complete the square in x and y.
x%5E2+%2B+y%5E2+-+2x+-+12+=+0
%28x%5E2-2x%29+%2B+%28y-0%29%5E2+-+12+=+0
%28x%5E2-2x%2B1%29+%2B+%28y-0%29%5E2+-+12+=+1
%28x-1%29%5E2%2B+%28y-0%29%5E2+=+13
Compare to the general equation for a circle centered at (h,k) with a radius R:
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
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(h,k)=(1,0)