SOLUTION: A furniture manufacturer can make from 30 to 60 tables a day and from 40 to 100 chairs a day. It can make at most 120 units in one day. The profit on a table is $150, and the prof

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: A furniture manufacturer can make from 30 to 60 tables a day and from 40 to 100 chairs a day. It can make at most 120 units in one day. The profit on a table is $150, and the prof      Log On


   



Question 346507: A furniture manufacturer can make from 30 to 60 tables a day and from 40 to 100 chairs a day. It can make at most 120 units in one day. The profit on a table is $150, and the profit on a chair is $65. How many tables and chairs should they make per day to maximize profit. How much is the maximum profit?
P= 150x + 65 y
30 <= x <= 60
40 <= y <= 100
x + y <= 120
x => 0
y => 0
Graph your system of inequalities
Label the vertices and find their coordinates

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the vertices.
x=30,y=40
(30,40)
x=60,y=40
(60,40)
x%2By=120
30%2By=120
y=90
(30,90)
x%2By=120
60%2By=120
y=60
(60,60)
.
.

.
.
The maximum (and minimum) values occur(s) at the vertices.
(30,40):P=+150x+%2B+65y=150%2830%29%2B65%2840%29=7100
(60,40):P=+150x+%2B+65y=150%2860%29%2B65%2840%29=11600
(30,90):P=+150x+%2B+65y=150%2830%29%2B65%2890%29=10350
(60,60):highlight%28P=+150x+%2B+65y=150%2860%29%2B65%2860%29=12900%29
Make 60 of each to maximize profits.