SOLUTION: Write 2x + y = 5 in polar form.
a. -sqrt 5 = r cos(theta - 27 degree)
b. sqrt 5 = r cos(theta - 27 degree)
c. -sqrt 5 = r cos(theta + 27 degree)\
d. sqrt 5 = r cos(theta + 2
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-> SOLUTION: Write 2x + y = 5 in polar form.
a. -sqrt 5 = r cos(theta - 27 degree)
b. sqrt 5 = r cos(theta - 27 degree)
c. -sqrt 5 = r cos(theta + 27 degree)\
d. sqrt 5 = r cos(theta + 2
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Question 346140: Write 2x + y = 5 in polar form.
a. -sqrt 5 = r cos(theta - 27 degree)
b. sqrt 5 = r cos(theta - 27 degree)
c. -sqrt 5 = r cos(theta + 27 degree)\
d. sqrt 5 = r cos(theta + 27 degree) Answer by CharlesG2(834) (Show Source):
You can put this solution on YOUR website! Write 2x + y = 5 in polar form.
a. -sqrt 5 = r cos(theta - 27 degree)
b. sqrt 5 = r cos(theta - 27 degree)
c. -sqrt 5 = r cos(theta + 27 degree)\
d. sqrt 5 = r cos(theta + 27 degree)
2x + y = 5
the above is standard form of a linear equation
in form Ax + By = C, above A = 2, B = 1, and C = 5
use x = rcos(theta) and y = rsin(theta), where r^2 = x^2 + y^2 and
tan(theta) = y/x
2(rcos(theta)) + rsin(theta) = 5 (substituted in values)
2rcos(theta) + rsin(theta) = 5
r(2cos(theta) + sin(theta)) = 5 (factor out the r)
r = 5/(2cos(theta) + sin(theta))
(