SOLUTION: show why the following problem has no solution. find 3 consecutive odd whole numbers whose sum is 102.

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Question 345937: show why the following problem has no solution. find 3 consecutive odd whole numbers whose sum is 102.
Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
N%2BN%2B2%2BN%2B4=102
3N%2B6=102
3N=96
96 is not divisible by 3.
So there is no integer (whole number) solution.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
show why the following problem has no solution. find 3 consecutive odd whole numbers whose sum is 102.

Let 1st number be F

Then the other 2 consecutive odd numbers are: F + 2 and F + 4

Since their sum is 102, then we'll have: F + F + 2 + F + 4 = 102

3F + 6 = 102

3F = 96

F = 96%2F3 = 32

This means that the 1st ODD NUMBER is 32, but because 32 is NOT an odd number but an EVEN NUMBER instead, there is NO solution.

As such, NO 3 WHOLE CONSECUTIVE ODD NUMBERS sum to 102.