SOLUTION: p^2+7p+12>o.....this is what i got p>-4....p>-3 i try to graph it the answer given to us is <-------)-4 -3(----------> if i get >-4 >-3 why is the answer <-4 >-3

Algebra ->  Radicals -> SOLUTION: p^2+7p+12>o.....this is what i got p>-4....p>-3 i try to graph it the answer given to us is <-------)-4 -3(----------> if i get >-4 >-3 why is the answer <-4 >-3      Log On


   

Question 345667: p^2+7p+12>o.....this is what i got p>-4....p>-3 i try to graph it the answer given to us is <-------)-4 -3(----------> if i get >-4 >-3 why is the answer <-4 >-3
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the factors are (p + 3) and (p + 4)

for the product of the factors to be >0 ; either both factors are >0 , OR both factors are <0

p + 3 > 0 ___ p > -3
p + 4 > 0 ___ p > -4

p + 3 < 0 ___ p < -3
p + 4 < 0 ___ p < -4

p must be > -3 AND -4 (which means greater than -3) , OR < -3 AND -4 (which means less than -4)