You can put this solution on YOUR website! Let A = A's present age
Let B = B's present age
;
In a years, A will be n times as old as B then;
A + a = n(B + a)
A + a = nB + na
A = nB + na - a; is A's present age
and b years ago, A was m times as old as B.
A - b = m(B - b)
Find B
m(B - b) = A - b
B - b =
B = + b; is B's present age