Question 345362: how do i factor 8x^2+5x-3
how do I factor t^2-8t-6t+48
Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! 8x^(2)+5x-3
In this problem 1*-(3)/(8)=-3 and 1-(3)/(8)=5, so insert 1 as the right hand term of one factor and -(3)/(8) as the right-hand term of the other factor.
(x1)(x-(3)/(8))
Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
(x+1)(8x-3)
t^(2)-8t-6t+48
Since -8t and -6t are like terms, subtract 6t from -8t to get -14t.
t^(2)-14t+48
In this problem -6*-8=48 and -6-8=-14, so insert -6 as the right hand term of one factor and -8 as the right-hand term of the other factor.
(t-6)(t-8)
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