SOLUTION: Solve in inequality of (4x - 2)/7 < x + 1 and write it in inverval notation
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Question 345359
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Solve in inequality of (4x - 2)/7 < x + 1 and write it in inverval notation
Answer by
mananth(16949)
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(4x - 2)/7 < x + 1
multiply by 7
(4x-2)/7 * 7 <7(x+1)
4x-2<7x+7
+2
4x<7x+7+2
4x<7x+9
add -7x
4x-7x<7x-7x+9
-3x<9
/-3
x>-3
...
(-3,OO)