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Question 345346: How do I solve 64x^3-1
Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! 64x^(3)-1=0
Since -1 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 1 to both sides.
64x^(3)=1
Divide each term in the equation by 64.
(64x^(3))/(64)=(1)/(64)
Simplify the left-hand side of the equation by canceling the common factors.
x^(3)=(1)/(64)
Take the cube root of both sides of the equation to eliminate the exponent on the left-hand side.
x=~3:((1)/(64))
Split the fraction inside the radical into a separate radical expression in the numerator and the denominator. A fraction of roots is equivalent to a root of the fraction.
x=(1)/(~3:(64))
Pull all perfect cube roots out from under the radical. In this case, remove the 4 because it is a perfect cube.
x=(1)/(4)
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