SOLUTION: solve this exponential equation to the nearest hundreth 2e^4x=8 help :(

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Question 34520: solve this exponential equation to the nearest hundreth
2e^4x=8
help :(
Found 2 solutions by Earlsdon, stanbon:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
2e%5E%284x%29+=+8 Divide both sides by 2.
e%5E%284x%29+=+4 Take the natural log (ln) of both sides.
ln%28e%5E%284x%29%29+=+ln%284%29 Simplify.
4x%2Aln%28e%29+=+ln%284%29 But ln(e) = 1
4x+=+ln%284%29
x+=+%28ln%284%29%29%2F4
x+=+0.35

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Divide both sides by "2" to get:
c^(4x)=4
Take the natural log of both sides to get:
4x=ln4
4x=1.38629...
x=0.34657...
Cheers,
Stan H.