SOLUTION: The dimensions of a rectangle are such that its length is 7 in more than its width. If the length were doubled and if the width were decreased by 3 in, the area would be increased

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Question 345198: The dimensions of a rectangle are such that its length is 7 in more than its width. If the length were doubled and if the width were decreased by 3 in, the area would be increased by 198 in^2 what are the length and width of the rectangle
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
L=W+7
LW=AREA
(W+7)W=AREA
W^2+7W=AREA
2L(W-3)=W^2+7W+198
2(W+7)(W-3)=W^2+7W+198
2(W^2+4W-21-W^2-7W-198=0
2W^2+8W-42-W^2-7W-198=0
W^2+W-240=0
(W+16)(W-15)=0
W-15=0
W=15 ANS. ORIGINAL WIDTH.
L=15+7=22 ANS. ORIGINAL LENGTH.
2*22=42 EXPANDED LENGTH.
15-3=12 EXPANDED WIDTH.
(2*22)(15-3)=15^2+7*15+198
44*12=225+105+198
528=528