SOLUTION: Find a polynomial for the perimeter and for the area. z+2 is the width on the top of the box z is the right side of the box. The perimeter is The area is

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find a polynomial for the perimeter and for the area. z+2 is the width on the top of the box z is the right side of the box. The perimeter is The area is       Log On


   



Question 345078: Find a polynomial for the perimeter and for the area.
z+2 is the width on the top of the box
z is the right side of the box.
The perimeter is
The area is

Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Usually we talk about rectangles having length (shown as 'l') and width (shown as 'w'), so the P = 2l + 2w.
You have the values to substitute for 'l' and 'w'
l+=+z%2B2
w+=+z
P+=+2l+%2B+2w+=+2%2A%28z%2B2%29+%2B+2%2Az++=+2z+%2B+4+%2B+2z
Collecting terms, we have
P+=+4z+%2B+4
The area is found much the same way.
We know the area (A) of a rectangle = length times width = l * w.
Substituting what we know about l and w, we have:
A+=+%28z%2B2%29+%2A+z+=+z%5E2+%2B+2z
Done.