Question 344874: Four engineers A,B,C and D have been scheduled for job interviews. The personnel manager has scheduled the four for interview rooms 1,2,3,and 4 respectively. However the manager's secretary does not know this, so assigns them to the four rooms in a completely random fashion. What is the probability that
A. All four end up in the correct rooms?
B. None of the four end up in the correct room?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Four engineers A,B,C and D have been scheduled for job interviews. The personnel manager has scheduled the four for interview rooms 1,2,3,and 4 respectively. However the manager's secretary does not know this, so assigns them to the four rooms in a completely random fashion. What is the probability that
A. All four end up in the correct rooms? (1/4)^4 = 0.0039
-------------------------------------------------------
B. None of the four end up in the correct room? (3/4)^4 = 0.3164
==============
Cheers,
Stan H.
|
|
|
