SOLUTION: the product two positive consecutive odd integers is 23 more than 5 times in sum. Find these two positive intergers

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Question 344786: the product two positive consecutive odd integers is 23 more than 5 times in sum. Find these two positive intergers
Answer by checkley77(12844) About Me  (Show Source):
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LET X & X+2 BE THE 2 POSITIVE INTEGERS.
X(X+2)=5(X+X+2)+23
X^2+2X=5(2X+2)+23
X^2+2X=10X+10+23
X^2+2X-10X-10-23=0
X^2-8X-33=0
(X-11)(X+3)=0
X-11=0
X=11 ANS.
PROOF:
11(11+2)=5(11+11+2)+23
11*13=5*24+23
143=120+23
143=143