SOLUTION: A triangle has a side of length x . The second side of the triangle is 2 inches longer than the first side. The third side is 4 inches longer than the first side. The squar

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A triangle has a side of length x . The second side of the triangle is 2 inches longer than the first side. The third side is 4 inches longer than the first side. The squar      Log On


   



Question 344438: A triangle has a side of length x . The second side of the triangle is 2 inches
longer than the first side. The third side is 4 inches longer than the first side. The
square of the first side plus the square of the second side is equal to the square of the
third side. What is the length if each side of the triangle? USE THE 5-STEP METHOD.
This is how much I've figured out so far:
x²+(x+2)²=(x+4)²
x²+x²+2x+2x+4 = x²+4x+4x+16
x(4)+4+4 = x²+8x+16
-4x -4x
x(4)+4 = x² +4x+16
x(4)+4-4 = x²+4x+16-4
x(4) = x²+4x+12
-x² = -x²
So if x²=4x+12, SOLVE FOR X.
I think the answer is 6, but I don't know the procedure.
I.E,
x=5 x=6
25=20+12 36=24+12
25=32 36=36
6²+8²+10²
36+64 =100
x=6
I need help ASAP, please!!! Thank you!! :)

Found 3 solutions by Alan3354, ewatrrr, vleith:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x²+(x+2)²=(x+4)²
x²+x²+2x+2x+4 = x²+4x+4x+16 It's ok this far
---------
x(4)+4+4 = x²+8x+16 ????
-------------
2x%5E2+%2B+4x+%2B+4+=+x%5E2+%2B+8x+%2B+16
x%5E2+-+4x+-+12+=+0
(x-6)(x+2) = 0
x = -2 (Ignore)
x = 6

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
So if x²=4x+12, SOLVE FOR X.
Quadratic equation:
x%5E%282%29-4x-12+=0
which can be factored:
(x-6)(x+2)=0
(x-6)=0
x=6

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Up to here you are golden
x%5E2%2Bx%5E2%2B2x%2B2x%2B4+=+x%5E2%2B4x%2B4x%2B16
2x%5E2+%2B+4x+%2B+4+=+x%5E2+%2B+8x+%2B+16 move everything to one side
2x%5E2+%2B+4x+%2B+4+-+x%5E2+-8x+-+16+=+0
x%5E2+-+4x+-+12+=+0
%28x-6%29%28x%2B2%29+=+0
So either (x-6 = 0) or (x+2=0)
Thus x = 6 or x = -2
Since the length of a side cannot be -2, then x must be 6
If x = 6, then x+2 = 8 and x + 4 = 10
Get it?