SOLUTION: how do you write the equation of a line in standard form with a slope of 3 and ay intercept of 2

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Question 34437: how do you write the equation of a line in standard form with a slope of 3 and ay intercept of 2

Answer by dimndskier(8) About Me  (Show Source):
You can put this solution on YOUR website!
OK, consider the equation +y+=+mx+%2B+b+
You substitute the slope give in for m. and subsitute the y-intercept in for b.
However, I believe standard form is +Ax+%2B+By+%2B+C+=+0+.
Essentially in order to do this take it from the form of y=mx+b and multiply everything by the denominator of the slope, and finally get everything on one side of the equation setting it equal to zero.
For an example:
Let's say we have a slope of 3/2 and a y-intercept of 2, then we should end up with:
+m+=+3%2F2+, and +b+=+2+, therefore we end up with the slope-intercept equation of:
+y+=+%283%2F2%29x+%2B+2+ to convert this to standard form, mulitply everything by 2 (because that is the denominator of 3/2 ).

So we get +%282%29%2Ay+=+%282%29%2A%283%2F2%29x+%2B+%282%29%2A2+, resulting in
+2y+=+3x+%2B+4+ ,but we still have to get everything on ONE side of the equal sign, BUT a special rule you must not... the coefficient A... MUST ALWAYS be positive, never negative so you have to make the appropriate adjustments.
So, my suggestion in this example is- since 3x is already positive (the 3 is positive) bring the 2y to the right side of the equation (leaving zero in its place).
+2y+-+%282y%29+=+3x+-+%282y%29+%2B+4+, resulting in
+0+=+3x+-+2y+%2B+4+, but rearrange with zero on the right side!
+3x-2y%2B4+=+0+