SOLUTION: log(x-3)+log(2)=1
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Question 344348
:
log(x-3)+log(2)=1
Answer by
fractalier(6550)
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From log(x-3)+log(2)=1
we apply the laws of logs and get
log(2(x-3)) = 1
log(2x - 6) = 1
now exponentiate each side to the base ten and get
2x - 6 = 10
2x = 16
x = 8