SOLUTION: I am trying to figure out how to solve for "n" when it is 2 to the "n" power in the following equation: 2^n+6=14. 2^n+6-6=14-6 2^n=8 I am unclear where to go from here. How to

Algebra ->  Exponents -> SOLUTION: I am trying to figure out how to solve for "n" when it is 2 to the "n" power in the following equation: 2^n+6=14. 2^n+6-6=14-6 2^n=8 I am unclear where to go from here. How to      Log On


   

Question 344317: I am trying to figure out how to solve for "n" when it is 2 to the "n" power in the following equation:
2^n+6=14.
2^n+6-6=14-6
2^n=8
I am unclear where to go from here. How to I isolate the exponent "n" to find the solution?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You could recognize that
8=2%5E3 and substitute.
2%5En=2%5E3
n=3
or take the log (base 2) of both sides.
log%282%2C%282%5En%29%29=log%282%2C%288%29%29
n=log%282%2C%288%29%29
n=log%2810%2C%288%29%29%2Flog%2810%2C%282%29%29
n=0.90309%2F0.30103
n=3