SOLUTION: I need help solving this problem. Please help. The problem: Hal hiked half his planned trip the first day. Because he became tired, he covered only half of the remaining dista

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Question 344165: I need help solving this problem. Please help.
The problem:
Hal hiked half his planned trip the first day. Because he became tired, he covered only half of the remaining distance on the third day. On the fourth day, he hiked three miles, which was one-fifth of the number of miles left. How many miles did he hike during the four days?
I tried doing this equation, but I was not sure if I did it right:
1/2x+1/3x+1/4x+3=15

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = length of the planned trip in miles
The 1st day he hiked x%2F2 miles
The remaining distance is x%2F2 miles
On the 3rd day, he hiked half of that, or
%281%2F2%29%2A%28x%2F2%29+=+x%2F4 miles
So far he has hiked x%2F2+%2B+x%2F4+=+%283x%29%2F4 miles
There are x%2F4 miles left
On the 4th day, he hiked 3 miles
Reading carefully, the problem is telling me that
the 3 miles he traveled on day 4 was 1/5 of the
x%2F4 miles left , so
3+=+%281%2F5%29%2A%28x%2F4%29
3+=+%281%2F20%29%2Ax
x+=+60 miles is the length of the planned trip
---------------------
Now, going back over the problem:
The 1st day he hiked x%2F2+=+30 miles
On the 3rd day, he hiked half of that, or
%281%2F2%29%2A30+=+15 miles
So far he has hiked 30+%2B+15+=+45 miles
and there are x%2F4+=+15 miles left
On the 4th day he hiked 3 miles which is
1%2F5 of the miles left, or %281%2F5%29%2A15+=+3
So, he hiked 30+%2B+15+%2B+3+=+48 of the
60 mile planned trip