SOLUTION: Five times the smallest of three consectutive odd integers is ten more than twice the largest. find the integers

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Five times the smallest of three consectutive odd integers is ten more than twice the largest. find the integers      Log On


   

Question 344152: Five times the smallest of three consectutive odd integers is ten more than twice the largest. find the integers
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
LET X, X+2 & X+4 BE THE 3 INTEGERS.
5X=2(X+4)+10
5X=2X+8+10
5X-2X=18
3X=18
X=18/3
X=6 ans. for the smaller integer.
6+4=10 ans. for the largest integer.
Proof:
5*6=2*10+10
30=20+10
30=30