Question 344067: Hii. Working on algebra two word problems and it so frustraiting!
1)ace rent a car charges a flat fee of $15 and $0.24 a mile for their cars. Acme rent a car charges a flat fee of $29 and $0.14 a mile for their cars. Use the following model to find out after how many miles ace rent a car becomes more expensive then acme rent a car.
Found 2 solutions by JBarnum, solver91311:
Answer by JBarnum(2146)   (Show Source):
Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
And I'll bet you can imagine just how frustrating it is for me to read your post when you misspell 'frustrating'. So depressing, discouraging, disheartening, and disconcerting. Ah well, perhaps someday you will grow up enough to have the courtesy to proofread your written communications before you send them.
Let  represent the number of miles traveled.
Then:
\ =\ 0.24x\ +\ 15)
Represents the total cost in dollars of renting from Company #1 for miles.
Whereas:
\ =\ 0.14x\ +\ 29)
Represents the total cost in dollars of renting from Company #2 for miles.
Clearly, for small values of ,  is less expensive. Substitute 1 mile for in each of the functions and see which is smaller, i.e. less expensive.
Also, for large values of ,  becomes less expensive at some point. Substitute 1000 for in each of the functions and see which is smaller, i.e. less expensive.
Somewhere between 1 mile and 1000 miles is a point where the cost of both becomes equal. This is called the break-even point. Mileage below the breakeven point makes  less, above the breakeven point makes  less.
The breakeven point is where the two costs are equal:
\ =\ C_2(x))
But we can replace each side of this equation with the expressions they are equal to:
Solve for .
John
My calculator said it, I believe it, that settles it
|
|
|
