SOLUTION: Decompose into partial fractions: 3x^2+13x+20/x^3+4x^2+4x

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Question 343996: Decompose into partial fractions:
3x^2+13x+20/x^3+4x^2+4x
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

3x%5E2%2B13x%2B20=A%28x%2B2%29%5E2%2BBx%28x%2B2%29%2BCx
3x%5E2%2B13x%2B20=A%28x%5E2%2B4x%2B4%29%2BB%28x%5E2%2B2x%29%2BCx
1.x%5E%282%29:A%2BB=3
2.x%5E%281%29:4A%2B2B%2BC=13
3.x%5E%280%29:4A=20
From eq. 3,
A=5
From eq. 1,
5%2BB=3
B=-2
From eq. 2,
4%285%29%2B2%28-2%29%2BC=13
20-4%2BC=13
C=-3
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