SOLUTION: a certain radio active isotope decays at a rate of .2% annually. Determine the half life of the isotope, to the nearest year.

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Question 343621: a certain radio active isotope decays at a rate of .2% annually. Determine the half life of the isotope, to the nearest year.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(1 - .002)^h = 1/2

h * log(1 - .002) = log(1/2)

h = [log(1/2)] / [log(1 - .002)]