SOLUTION: the sum of three consective even integers is 48 more than twice the smallest of the three integers. find the integers.

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Question 343425: the sum of three consective even integers is 48 more than twice the smallest of the three integers. find the integers.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
NOTE: QUESTION STATES "CONSECUTIVE EVEN INTEGERS"
LET E[1] REPRESENT THE FIRST OF THE THREE "CONSECUTIVE EVEN INTEGERS"
THE QUESTION STATES THE FOLLOWING TO BE TRUE:
E%5B1%5D%2B%28E%5B1%5D%2B2%29%2B%28E%5B1%5D%2B4%29=2%28E%5B1%5D%29%2B48
SOLVE:
COMBINE
3E%5B1%5D+%2B6+=+2%28E%5B1%5D%29%2B48
SUBTACT 2E%5B1%5D FROM BOTH SIDES OF THE EQUATION
E%5B1%5D+%2B6+=+48
SUBTACT 6 FROM BOTH SIDES OF THE EQUATION
E%5B1%5D=+42 CONSECUTIVE EVEN INTEGERS ARE 42,44,46
CHECK YOUR ANSWER!! 42+44+46 = 132 = 84 +48