SOLUTION: How do I solve
the following expressions of the product of 3 less than twice x and 2 more than the quality of 3 times x?
the answers to choose from are:
A. neg.6xsquared+25x
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: How do I solve
the following expressions of the product of 3 less than twice x and 2 more than the quality of 3 times x?
the answers to choose from are:
A. neg.6xsquared+25x
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Question 343373: How do I solve
the following expressions of the product of 3 less than twice x and 2 more than the quality of 3 times x?
the answers to choose from are:
A. neg.6xsquared+25x+6
B. 6x squared+5x+6
C. 6x squared-5x+6
D. 6x squared-5x-6
E. 6x squared-13x-6 Found 2 solutions by J2R2R, stanbon:Answer by J2R2R(94) (Show Source):
You can put this solution on YOUR website! How do I solve the following expressions of the product of 3 less than twice x and 2 more than the quality of 3 times x?
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(2x-3)(3x+2) = 6x^2+4x-9x-6 = 6x^2-5x-6
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Cheers,
Stan H.
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the answers to choose from are:
A. neg.6xsquared+25x+6
B. 6x squared+5x+6
C. 6x squared-5x+6
D. 6x squared-5x-6
E. 6x squared-13x-6
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