SOLUTION: in ax^2+bx+c form, what is 8-2x^2=(x+2)^2-7?

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Question 342733: in ax^2+bx+c form, what is 8-2x^2=(x+2)^2-7?
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
8-2x^2=(x+2)^2-7


8-2x^2=x^2+4x+4-7


0=x^2+4x+4-7+2x^2-8

0=3x^2+4x-11


3x^2+4x-11 <----- Answer