Question 342697: In a recent study 90 percent of the homes in the United States were found to have color TVs. In a sample of nine homes, what is the probability that:
a. All nine have color TVs?
b. Less than five have color TVs?
c. More than five have color TVs?
d. At least seven homes have color TVs?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a recent study 90 percent of the homes in the United States were found to have color TVs. In a sample of nine homes, what is the probability that:
a. All nine have color TVs?
Ans: 0.9^9 = 0.3874
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b. Less than five have color TVs?
Ans: binomcdf(9,0.9,4) = 0.0008909...
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c. More than five have color TVs?
Ans: 1 - binomcdf(9,0.9,5) = 1 - 0.0083 = 0.9917
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d. At least seven homes have color TVs?
Ans: 1 - binomcdf(9,0.9,6) = 1-0.0530 = 0.9470
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Cheers,
Stan H.
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