SOLUTION: Find values of c so that the equation will have two solutions, one solution, and no real solution. x^2+4x+c=0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find values of c so that the equation will have two solutions, one solution, and no real solution. x^2+4x+c=0      Log On


   

Question 34261This question is from textbook McDougal Littell Algebra1
: Find values of c so that the equation will have two solutions, one solution, and no real solution.
x^2+4x+c=0 This question is from textbook McDougal Littell Algebra1

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
To find values of c you need values for x, but we can simplify:
x^2+4x+c=0
(x^2+4x)=-c
(x + 2)^2 = 4 - c
4 - (x + 2)^2 = c
The answer for c depends on the value for x. With the information you provided, we can assume that any number can be used for x.... so infinitely many.