SOLUTION: Find the equation of a circle satisfying the conditions given. Then sketch the graph. center (1, -2), diameter 6 if the radius is half of the diameter, wouldn't the radius be

Algebra ->  Graphs -> SOLUTION: Find the equation of a circle satisfying the conditions given. Then sketch the graph. center (1, -2), diameter 6 if the radius is half of the diameter, wouldn't the radius be      Log On


   

Question 342423: Find the equation of a circle satisfying the conditions given. Then sketch the graph.
center (1, -2), diameter 6
if the radius is half of the diameter, wouldn't the radius be 3? The solution manual is saying the radius is 2 times the square root of 3.
Please explain in detail how to get the correct answer.
Thank you.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
you are correct about the radius ___ sounds like an error in the system somewhere

the general equation for a circle of radius "r" , centered at (h,k) is ___ (x - h)^2 + (y - k)^2 = r^2

in this case ___ (x - 1)^2 + (y + 2)^2 = 9