SOLUTION: the equation 5x^2+14x+1=0 has two solutions A and B where a<b what is the answer because i have tried every kind of way to solve it and its always wrong

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Question 342266: the equation 5x^2+14x+1=0 has two solutions A and B where a
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Have you tried the quadratic formula?
It works for any quadratic equation.
5x%5E2%2B14x%2B1=0
a=5
b=14
c=1
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-14%2B-+sqrt%28+14%5E2-4%2A5%2A1+%29%29%2F%282%2A5%29+
x+=+%28-14%2B-+sqrt%28+196-20+%29%29%2F%2810%29+
x+=+%28-14%2B-+sqrt%28+176+%29%29%2F%2810%29+
x+=+%28-14%2B-+4%2Asqrt%28+11+%29%29%2F%2810%29+
x+=+%28-7%2B-+2%2Asqrt%28+176+%29%29%2F%285%29+
.
.
.
B+=+%28-7%2B+2%2Asqrt%28+176+%29%29%2F%285%29+
A+=+%28-7-+2%2Asqrt%28+176+%29%29%2F%285%29+
So that A%3CB