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Question 342232: Find an equation of the line containing the point (- 6, - 9) and parallel to the line containing the points (- 6, 5) and (3, - 21). Write the equation in general form: Ax + By = C.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find an equation of the line containing the point (- 6, - 9) and parallel to the line containing the points (- 6, 5) and (3, - 21). Write the equation in general form: Ax + By = C.
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slope of the given line = (-21-5)/(3--6) = -26/9
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Find equation of line with m = -26/9 that passes thru (-6,-9).
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y = mx+b
-9 = (-26/9)(-6)+b
(-81/9) = (156/9) + b
b = (-237/9)
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Equation:
y = (-26/9)x -(237/9)
Multiply thru by 9 to get:
8y = -26x - 237
26x+8y = -237
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Cheers,
Stan H.
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