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Question 341756: Good evening. I am taking a college level business calculus class. We are currently reviewing algebra. I am stuck on one problem. It is:
A-5
---- < -1
A+2
I know to take the -1 times A + 2 to get A - 5 < A + 2 and I know to take the +2 and subtract it from A - 5 to get A - 5 - 2, but what happens to the A on the right side. Is it not supposed to be a 0? I am really confused and lost and, therefore, unable to continue because the rest of this section contains similar problems. Please help me figure this problem out.
Found 2 solutions by stanbon, Edwin McCravy: Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A-5
---- < -1
A+2
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The boundary of the inequality is (A-5)/(A+2) = -1
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Since the denominator cannot be zero, A cannot be -2.
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The numerator cannot be zero so A cannot be 5
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To solve the inequality:
1: Draw a number line
2: Plot the values A = -2 and A = 5
3: Check a test value from each of the resulting 3 intervals
to see where the solutions are for the inequality.
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A-5
---- < -1
A+2
Check A = -10; (-10-5)/(-10+2) < -1, false so no solutions in (-inf,-2)
Check A = 0; (0-5)/(0+2)< -1, true so solutions in (-2,5)
Check A = 10; (10-5)/(10+2) < -1, false so no solutions in (5,+inf)
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Final solution: -2< A < 5
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Graph:

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Cheers,
Stan H.
Answer by Edwin McCravy(20054) (Show Source):
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