SOLUTION: Could someone please help me with this problem? Solve. Where appropriate,include approximations to the nearest thousandth. if no solution exists, state this. log (x-3) + log

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Could someone please help me with this problem? Solve. Where appropriate,include approximations to the nearest thousandth. if no solution exists, state this. log (x-3) + log      Log On


   

Question 341711: Could someone please help me with this problem?
Solve. Where appropriate,include approximations to the nearest thousandth. if no solution exists, state this.
log (x-3) + log x= 1
thank you for your help.
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
log (x-3) + log x= 1


log [x(x-3)]= 1

x(x-3)=10^1

x^2-3x=10

x^2-3x-10=0

(x-5)(x+2)=0

x=5 or x=-2 (ignore)


Only solution is x=5