SOLUTION: The measure of the area of a rectangle is 6a^2+7a+2. The width is a binomial of the form ap+q. What is the measure of the perimeter of the rectangle?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The measure of the area of a rectangle is 6a^2+7a+2. The width is a binomial of the form ap+q. What is the measure of the perimeter of the rectangle?      Log On


   

Question 34162: The measure of the area of a rectangle is 6a^2+7a+2. The width is a binomial of the form ap+q. What is the measure of the perimeter of the rectangle?
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
Area is defined as L*W
so factor the area that is represented by the trinomial
+6a%5E2%2B7a%2B2+
+%283a%2B2%29%282a%2B1%29+
Perimiter is defined as 2(L+W)
so plug in the L and W that you factored
+2%28L%2BW%29=P+
+2%28%283a%2B2%29%2B%282a%2B1%29%29=P+
Add the terms in the parenthesis
+2%285a%2B3%29=P+
Distribute
+10a+%2B+6+=+P+
Without a value for a ... you are finished