SOLUTION: A square picture frame has an outer perimeter of 28 and an inner perimeter of 20. What is the shortest distance between any two vertices? a 5 b √2 c 2√2 d 7

Algebra ->  Rectangles -> SOLUTION: A square picture frame has an outer perimeter of 28 and an inner perimeter of 20. What is the shortest distance between any two vertices? a 5 b √2 c 2√2 d 7       Log On


   

Question 341321: A square picture frame has an outer perimeter of 28 and an inner perimeter of 20. What is the shortest distance between any two vertices?
a 5 b √2 c 2√2 d 7 e 7√2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

From the diagram,
P1=4%2As1=28
P2=4%2As2=20
s1=s2%2B2x
4s1=4s2%2B8x
8x=4s1-4s2
8x=28-20
8x=8
x=1
.
.
.
d%5E2=x%5E2%2Bx%5E2=2x%5E2
d=sqrt%282%29x
highlight%28d=sqrt%282%29%29