SOLUTION: Find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third angle measures 3 times the second angle decreased by

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Question 341194: Find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third angle measures 3 times the second angle decreased by 12.
Found 2 solutions by rfer, stanbon:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
2x+x+3x-12=180
6x=192
x=32 degrees
2x=64 degrees
3x-12=84 degrees

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third angle measures 3 times the second angle decreased by 12.
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Equations:
x + y + z = 180
x = 2y
z = 3y-12
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Substitute and solve for "y";
2y + y + 3y-12 = 180
6y = 192
y = 32 degrees
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x = 2y = 64 degrees
z = 3y-12 = 96-12 = 84 degrees
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Cheers,
Stan H.