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Question 341183: Two times the least of three consecutive odd integers exceeds three times the greatest by 15. What are the integeres?
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! Let's call the least of the three integers x. The next odd one is two more or x + 2, and the next is x + 4.
Then
2x - 15 = 3(x + 4)
We subtract the 15 since it exceeds three times the largest...so,
2x - 15 = 3x + 12
subtract 2x from both sides and then subtract 12...
-15 = x + 12
-27 = x
The numbers are -27, -25, and -23.
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