SOLUTION: if (x+3)/2 is an integer, then x must be A. a negative integer B. a positive integer C. a multiple of 3 D. an even integer E. an odd integer

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: if (x+3)/2 is an integer, then x must be A. a negative integer B. a positive integer C. a multiple of 3 D. an even integer E. an odd integer      Log On


   



Question 340872: if (x+3)/2 is an integer, then x must be
A. a negative integer
B. a positive integer
C. a multiple of 3
D. an even integer
E. an odd integer

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B3%29%2F2 is an integer

First we look at the 2 denominator.  In order for %28x%2B3%29%2F2
to end up being an integer the numerator x%2B3 must
be divisible by 2, which means that the whole numerator x%2B3 
must end up being an even integer.

Now we remember the rules for adding even and odd integers

1. even + even = even
2. even + odd = odd
3. odd + odd = even

We want x%2B3 to end up an even integer.

Now since 3 is odd, in order for x%2B3 to be an
even integer we must have the 3rd case.  That is, the only way 
to get an even integer for x%2B3 is to add an odd integer 
to the odd integer 3.

Therefore the correct answer is E.

Edwin