SOLUTION: The probability of contracting the kissing disease is .23 when one is exposed to a certain provocative environment. Sixty people are so exposed. What is the probability that no mo
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Question 340855: The probability of contracting the kissing disease is .23 when one is exposed to a certain provocative environment. Sixty people are so exposed. What is the probability that no more than 10 are infected with this dreaded disease? Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! There are 63 people.
The probability that 0 get the kissing disease is .23^0 * .77^60
The probability that exactly 1 gets the kissing disease is .23^1 * .77^59 * 60! / (1! * 59!)
The probability that exactly 2 get the kissing disease is .23^2 * .77^58 * 60! / (2! * 58!)
The probability that exactly 3 get the kissing disease is .23^3 * .77^57 * 60! / (3! * 57!)
Do this for up to 10 people.
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The probability that exactly 10 get the kissing disease is .23^10 * .77^50 * 60! / (10! * 50!)
Add up the probabilities of exactly 0 through exactly 10 and you get the probability that no more than 10 gets the kissing disease.
That becomes the probability of 0 or 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 or 10 getting the disease.
That probability will be, based on the following table: